Время

16:19:01
10 Февраля 2012
Пятёрка за неделю 22
Осталось: 2 дня
Конец: 11.02.2012 22:00
Лидер: mne2goda
Версия для печати

K-equivalence

   Consider a set K of positive integers.

   Let p and q be two non-zero decimal digits. Call them K-equivalent if the following condition applies:

   For every n 2 K, if you replace one digit p with q or one digit q with p in the decimal notation of n then the resulting number will be an element of K.

   For example, when K is the set of integers divisible by 3, the digits 1, 4, and 7 are K-equivalent. Indeed, replacing a 1 with a 4 in the decimal notation of a number never changes its divisibility by 3.

   It can be seen that K-equivalence is an equivalence relation (it is reflexive, symmetric and transitive).

   You are given a finite set K in form of a union of disjoint finite intervals of positive integers.

   Your task is to find the equivalence classes of digits 1 to 9.


Технические условия

   Input

   The first line contains n, the number of intervals composing the set K (1 ≤ n 10 000). Each of the next n lines contains two positive integers ai and bi that describe the interval [ai, bi] (i. e. the set of positive integers between ai and bi, inclusive), where 1 ≤ ai bi 1018. Also, for i  [2..n]: ai ¸ bi–1 + 2.

   Output

   Represent each equivalence class as a concatenation of its elements, in ascending order.

   Output all the equivalence classes of digits 1 to 9, one at a line, sorted lexicographically.


Информация о задаче

Лимит времени: 1 секунда
Лимит памяти: 64 MB
Баллы за пройденный тест: 7.14286
Автор: Mikhail Dvorkin

Пример

Пример входных данных

Sample 1
1
1 566

Sample 2
1
30 75

Пример выходных данных

Sample 1
1234
5
6
789

Sample 2
12
345
6
7
89


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